ICSE Class 10
Mathematics
Ratio and Proportion — Chapter Test
Time: 20 min
Maximum marks: 20
General instructions: Answer all questions. Marks are shown in brackets [ ].
Objective
-
1.
[1]The sub-triplicate ratio of $64:125$ is:
- A. $16:17$
- B. $61:340$
- C. $4:5$
- D. $\frac{64}{3}:\frac{125}{3}$
-
2.
[1]If $x, y$ and $z$ are in continued proportion, which of the following expressions simplifies to $\frac{x}{z}$?
- A. $\frac{(x + y)^2}{(y + z)^2}$
- B. $\frac{(x - y)^2}{(y - z)^2}$
- C. $\frac{(x + y)^2}{(y - z)^2}$
- D. $\frac{(x - y)^2}{(y + z)^2}$
-
3.
[1]What must be subtracted from each of the numbers 23, 30, 57, and 78 so that the resulting remainders are in proportion?
- A. 3
- B. 6
- C. 9
- D. 12
-
4.
[1]Divide Rs. 1162 among A, B, and C in the ratio 35:28:20. What is A's share?
- A. Rs. 490
- B. Rs. 350
- C. Rs. 560
- D. Rs. 420
-
5.
[1]The ratio between $3.6\,\mathrm{m}$ and $75\,\mathrm{cm}$ is:
- a. $18:275$
- b. $24:5$
- c. $6:125$
- d. $4:5$
-
6.
[1]Reena reduces her weight in the ratio 3:2. What is her weight now if originally it was 81 kg?
- A. 27 kg
- B. 54 kg
- C. 60 kg
- D. 121.5 kg
-
7.
[1]In a regiment, the ratio of the number of officers to the number of soldiers was $3 : 31$ before a battle. In the battle, 6 officers and 22 soldiers were killed. The ratio between the number of officers and the number of soldiers after the battle is $1 : 13$. What was the total number of officers and soldiers in the regiment before the battle?
- A. 238
- B. 245
- C. 210
- D. 196
-
8.
[1]If $x: y = 3:2$, find the value of $(5x - 3y): (7x + 2y)$.
- A. 3 : 5
- B. 9 : 25
- C. 15 : 23
- D. 5 : 7
-
9.
[1]6 is the mean proportion between two numbers $x$ and $y$, and 48 is the third proportional of $x$ and $y$. Which pair of numbers satisfies these conditions?
- A. $x = 2$, $y = 18$
- B. $x = 3$, $y = 12$
- C. $x = 4$, $y = 9$
- D. $x = 6$, $y = 6$
-
10.
[1]If $a, b, c$ are in continued proportion, which of the following correctly shows that $a : c$ is the duplicate ratio of $a$ to $b$?
- A. $\frac{a}{c} = \frac{a^2}{b^2}$ because $a = ck^2$ and $b = ck$ for some constant $k$.
- B. $\frac{a}{c} = \frac{b}{a}$ since $a, b, c$ are in continued proportion.
- C. $a : c = b : a$ as the duplicate ratio implies equality of ratios.
- D. $\frac{a}{c} = \frac{b^2}{a^2}$ because $b^2 = ac$ in continued proportion.
-
11.
[1]If $A : B = 2 : 3$, $B : C = 4 : 5$ and $C : D = 6 : 7$, then what is the combined ratio $A : B : C : D$?
- A. 8:12:15:14
- B. 16:24:30:35
- C. 4:6:7:8
- D. 16:20:25:35
-
12.
[1]Find the reciprocal ratio of: $\frac{x}{3} : \frac{y}{5}$
- A. $5x : 3y$
- B. $3y : 5x$
- C. $15xy : xy$
- D. $\frac{5}{y} : \frac{3}{x}$
-
13.
[1]If $ x = \frac{2ab}{a + b} $, find the value of: $ \frac{x + a}{x - a} + \frac{x + b}{x - b} $.
- A. 0
- B. 1
- C. 2
- D. $\frac{a + b}{a - b}$
-
14.
[1]If $2x + 3y: 3x + 5y = 18:29$, then the ratio $x:y$ is:
- a. $2:3$
- b. $3:5$
- c. $3:4$
- d. $5:29$
-
15.
[1]If $\frac{a}{b} = \frac{c}{d}$, which of the following correctly shows that $\frac{ma + nb}{mc + nd} = \frac{ma - nb}{mc - nd}$?
- A. By applying alternendo and componendo-dividendo to the given proportion, the equality is proved.
- B. Cross-multiplying the given proportion yields $ad = bc$, which directly proves the equality.
- C. Adding and subtracting $ma$ and $nb$ on both sides of the proportion proves the result.
- D. The equality holds because $\frac{ma + nb}{mc + nd} = \frac{a}{c}$ and $\frac{ma - nb}{mc - nd} = \frac{b}{d}$.
-
16.
[1]If $\frac{a}{b + c} = \frac{b}{c + a} = \frac{c}{a + b}$ and $a + b + c = 0$, what is the value of each given ratio?
- A. $1$
- B. $-1$
- C. $0$
- D. $\frac{1}{2}$
-
17.
[1]Solve the equation: $\frac{\sqrt{3x} + \sqrt{2x - 1}}{\sqrt{3x} - \sqrt{2x - 1}} = 5$. What is the value of $x$?
- A. $\frac{3}{2}$
- B. $\frac{2}{3}$
- C. $\frac{1}{2}$
- D. $3$
-
18.
[1]If $\frac{x}{a} = \frac{y}{b} = \frac{z}{c}$, which of the following correctly proves the equality $\frac{2x^3 - 3y^3 + 4z^3}{2a^3 - 3b^3 + 4c^3} = \left(\frac{2x - 3y + 4z}{2a - 3b + 4c}\right)^3$?
- A. Let $\frac{x}{a} = \frac{y}{b} = \frac{z}{c} = k$. Substitute $x = ak$, $y = bk$, $z = ck$ into both sides to show they equal $k^3$.
- B. Assume $x = a$, $y = b$, and $z = c$ directly, then simplify both sides to show they equal 1.
- C. Cross-multiply the given ratios to get $x = y = z$ and substitute into the equation to verify.
- D. Express $a$, $b$, and $c$ in terms of $x$, $y$, and $z$, then substitute into the left side only to simplify.
-
19.
[1]The monthly pocket money of Ravi and Sanjeev are in the ratio 5 : 7. Their expenditures are in the ratio 3 : 5. If each saves Rs. 80 every month, what is Ravi's monthly pocket money?
- A. Rs. 300
- B. Rs. 400
- C. Rs. 500
- D. Rs. 560
-
20.
[1]Given $\frac{x^3 + 12x}{6x^2 + 8} = \frac{y^3 + 27y}{9y^2 + 27}$, use componendo and dividendo to find the ratio $x:y$.
- A. $1:2$
- B. $2:3$
- C. $3:4$
- D. $4:5$
— End of paper —
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