ICSE Class 10
Mathematics
Linear Inequations (in one variable) — Chapter Test
Time: 20 min
Maximum marks: 20
General instructions: Answer all questions. Marks are shown in brackets [ ].
Objective
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1.
[1]Solve the inequation and determine its solution set: $4 - 5x > -11$, where $x \in I$. Which of the following represents the correct solution set?
- A. $\{x : x < 3, x \in I\}$
- B. $\{x : x > 3, x \in I\}$
- C. $\{x : x \leq 3, x \in I\}$
- D. $\{\dots, -1, 0, 1, 2, 3\}$
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2.
[1]If $3x - 7 > 5x - 1 \forall x \in R$ then:
- A. $x > -3$
- B. $x < -3$
- C. $x \leq -3$
- D. $x \geq -3$
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3.
[1]Solve the inequation and identify its solution set from the given options: $2x - 7 < 4$, $x \in \{1, 2, 3, 4, 5, 6, 7\}$.
- A. {1, 2, 3, 4, 5}
- B. {1, 2, 3, 4, 5, 6}
- C. {2, 3, 4, 5, 6}
- D. {1, 2, 3, 4}
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4.
[1]The solution set for the inequation $2x + 7 \leq 17$, $x \in N$ is:
- A. $\{1,2,3,4,5\}$
- B. $\{0,1,2,3,4,5\}$
- C. $\{1,2,3,4\}$
- D. $\{0,1,2,3,4\}$
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5.
[1]If $3(x - 1) \geq 2(x - 3)$ then:
- A. $x > -3$
- B. $x < -3$
- C. $x \leq -3$
- D. $x \geq -3$
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6.
[1]The solution set representing the following number line is: $$- \infty \leftarrow \begin{array}{cccccccc}1 & 1 & 1 & 1 & 1 & 1 & 1 \\ -5 & -4 & -3 & -2 & -1 & 0 & 1 & 2 & 3\end{array}$$
- A. $[x : x \in R, -3 \leq x < 2]$
- B. $[x : x \in R, -3 < x < 2]$
- C. $[x : x \in R, -3 \leq x \leq 2]$
- D. $[x : x \in R, -3 \leq x \leq 2]$
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7.
[1]Find the value(s) of x ∈ W that satisfy the inequation: -2 5/6 < 1/2 - (2x)/3 ≤ 2. Which set represents the solution?
- A. {0, 1, 2, 3, 4, 5}
- B. {1, 2, 3, 4}
- C. {0, 1, 2, 3, 4}
- D. {-1, 0, 1, 2, 3, 4}
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8.
[1]Solve the following inequation and select the correct solution set: $-2 + 10x \leq 13x + 10 \text{ < } 24 + 10x, x \in Z$. Represent this on the real number line as shown:

- A. $\{-4, -3, -2, -1, 0, 1, 2, 3\}$
- B. $\{-4, -3, -2, -1, 0, 1, 2, 3, 4\}$
- C. $\{-3, -2, -1, 0, 1, 2, 3, 4\}$
- D. $\{-5, -4, -3, -2, -1, 0, 1, 2, 3, 4\}$
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9.
[1]Solve the following inequation and identify the correct solution set: $$-2 < \frac{1}{2} - \frac{2x}{3} \leq \frac{11}{6}, x \in R.$$ Represent the solution set on the number line.

- A. $$\{x : -2 < x \leq \frac{15}{4}, x \in R\}$$
- B. $$\{x : -2 \leq x < \frac{15}{4}, x \in R\}$$
- C. $$\{x : x < -2, x \in R\}$$
- D. $$\{x : x \geq \frac{15}{4}, x \in R\}$$
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10.
[1]Multiplying $-3$ on both sides of a linear inequation $\frac{-2x + 7}{3} \leq \frac{-4x + 5}{3}$ becomes
- A. $-2x + 7 \geq -4x + 5$
- B. $2x - 7 \geq 4x - 5$
- C. $-2x + 7 \leq 4x - 5$
- D. $2x - 7 \leq 4x - 5$
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11.
[1]Solve the inequation and choose the correct solution set on a number line: $5(x - 2) > 4(x + 3) - 20$, where $x \in I$.
- A. $\{\dots, -3, -2, -1, 0, 1, 2, 3\}$
- B. $\{3, 4, 5, \dots\}$
- C. $\{\dots, -1, 0, 1, 2\}$
- D. $\{2, 3, 4, \dots\}$
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12.
[1]Reshma has ₹120 and wants to buy some registers and pens. The cost of one register is ₹40 and that of a pen is ₹20. The mathematical formulation of the given problem is:
- A. $40x + 20y = 120$
- B. $40x + 20y > 120$
- C. $40x + 20y \leq 120$
- D. $40x + 20y \geq 120$
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13.
[1]Solve the inequation -8½ < -½ - 4x ≤ 7½ for x ∈ I and identify the correct solution set.

- A. {-2, -1, 0, 1}
- B. {-3, -2, -1, 0, 1}
- C. {-1, 0, 1, 2}
- D. {x : -2 ≤ x < 2, x ∈ I}
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14.
[1]Given the sets: $A = \{x: 11x - 5 > 7x + 3, x \in \mathbb{R}\}$ and $B = \{x: 18x - 9 \geq 15 + 12x, x \in \mathbb{R}\}$, their intersection $A \cap B$ is represented on the number line below.
Which labeled part on the number line correctly shows the range of $A \cap B$?- A. An open circle at 2 with a ray extending to the right
- B. A closed circle at 2 with a ray extending to the right
- C. An open circle at 2 with a ray extending to the left
- D. A closed circle at 2 with a segment extending to 3
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15.
[1]The solution set of the inequations $-2 < 2x - 6$ or $-2x + 5 \geq 13$, where $x \in \mathbb{R}$, is represented on the number line below:
Which labeled part correctly indicates the darkened circle at $-4$ with an arrow extending to the left?- A. Label P: hollow circle at 2, arrow to the right
- B. Label Q: darkened circle at -4, arrow to the left
- C. Label R: hollow circle at -4, arrow to the right
- D. Label S: darkened circle at 2, arrow to the left
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16.
[1]Solve the inequation and determine its solution set for the given condition: $-x > -3x - 5$, $x \in I$. Which of the following represents the correct solution set?
- A. $\{-3, -2, -1, 0, 1, 2, \dots\}$
- B. $\{-2, -1, 0, 1, 2, \dots\}$
- C. $\{\dots, -3, -2, -1, 0\}$
- D. $\{-1, 0, 1, 2, 3, \dots\}$
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17.
[1]The number of pairs of consecutive odd natural numbers both of which are larger than 10, such that their sum is less than 40, is
- A. 8
- B. 6
- C. 4
- D. 3
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18.
[1]Solve the following system of inequations and identify the correct solution set: $$3 - x \leq 2(x - 3) \text{ and } 5 - x > x - 7, x \in R.$$ Graph the solution set.

- A. $$\{x : 1 \leq x < 3, x \in R\}$$
- B. $$\{x : \frac{8}{5} \leq x < 3, x \in R\}$$
- C. $$\{x : x \geq 3, x \in R\}$$
- D. $$\{x : x < \frac{8}{5}, x \in R\}$$
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19.
[1]The longest side of a triangle is 3 times the shortest side and the third side is $2\,\mathrm{cm}$ shorter than the longest side. If the perimeter of the triangle is at least $61\,\mathrm{cm}$, then minimum length of the shortest side is
- A. $7\,\mathrm{cm}$
- B. $8\,\mathrm{cm}$
- C. $9\,\mathrm{cm}$
- D. $10\,\mathrm{cm}$
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20.
[1]Solve the following inequation and select the correct solution set from the options below: (-x)/3 ≤ x/2 - 1 1/3 < 1/6, x ∈ R.

- A. {x: 1.6 ≤ x < 3, x ∈ R}
- B. {x: x ≤ 1.6 or x > 3, x ∈ R}
- C. {x: 1.6 < x ≤ 3, x ∈ R}
- D. {x: x < 1.6 or x ≥ 3, x ∈ R}
— End of paper —
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